Does any one have any advice on how I would go about solving this problem? I'm pretty confused.?

In a local bar, a customer slides an empty beer mug down the counter for a refill. The bartender is momentarily distracted and does not see the mug, which slides off the counter and strikes the floor 1.10 m from the base of the counter. The height of the counter is 0.86 m.


(a) With what velocity did the mug leave the counter?


(b) What was the direction of the mug's velocity just before it hit the floor?


Does any one have any advice on how I would go about solving this problem? I'm pretty confused.?
Treat the horizontal and vertical motions separately


Vertical - The mug is falling 0.86 m under gravitational accleration (g). You can then work out how long it takes to fall using


s = ut + 0.5 x g x t ^2 where u, the initial velocity is 0


so 0.86 = 0.5 x 9.81 x t^2 and t can be calculated


the velocity with which it hits the floor can be calculated using


v = u + at


Horizontal - Knowing the time t the horizontal speed can be calculated assuming that it doesn't slow down ( which of course it does in real life) using v = s/t .


The angle of striking can be done knowing the horizontal and vertical velocities and using a triangle of vectors.


I have not worked these out as I assume you will get more satisfaction out of doing them yourselfd. good luck